Infosys Placement Papers with Solutions 2023 | Infosys Previous Papers with Solutions PDF | Infosys last 5 years Placement Papers with solutions/ Infosys Pseudocode Questions and Answers PDF Download
Infosys Placement Papers with Solutions 2023: Here you can get Infosys’s last 5 years’ Placement Papers with solutions PDF, Infosys Aptitude Test Papers with Answers PDF, etc. for free cost. In this article, we have given detailed information about the Infosys Coding questions PDF, Infosys placement papers, Infosys Previous year Question Papers with Answers PDF & others. The system for Infosys placement sheets 2022 has now been completely changed. Naukrimessenger.com provides you with all the up-to-date information on the Infosys Placement Sheets 2022 change. Only registered interviewees will appear for the Infosys Online trial at the confirmed date and time using the link shared with them by the Infosys Talent Acquisition Team and a one-time password. Get detailed information about Infosys Exam Pattern, syllabus, previous year questions, etc. in the below section
In the below section we have provided the latest & new Infosys Placement Papers pattern & syllabus 2023, check it out
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Here we have given the brief information about the Infosys Placement Paper for Freshers. From this page you can get the Infosys Previous Year Paper Puzzle Solving 2022 Memory-Based, Infosys Previous Year Paper Reasoning Ability 2022 Memory-Based, Mathematical Ability, and Logical Reasoning 2023 Memory-Based, Verbal Ability Previous Year Paper 2022 Memory-Based, etc. Without skipping anything read the entire article for the detailed information about the Infosys Subject-wise Practice Placement Papers
Infosys Previous year question papers with answers
For more details regarding Infosys recruitment, Exam pattern, syllabus, old model papers, Freshers off campus drive, Exam date, Admit card, Result & many others instantly visit our Naukrimessenger.com
Infosys Previous Year Question Paper with Answers PDF | Infosys Subject-wise Practice Placement Papers
The Infosys paper is divided into three sections: Logical Rational, Quantitative and Verbal. In order for Infosys to be considered for the job, all of these areas must be qualified with high scores. To help you with that, we have provided Infosys’ previous year’s papers
Applicants should also try Infosys training packages. It is essential to prepare each subject for the Infosys exam Judging the Infosys Practice Exam of each syllabus topic will strengthen your knowledge and help you get good marks.
Solving Infosys’ previous year’s questionnaires will help you identify your weak points. You can work on your time accuracy by trying out Infosys’ previous year’s papers. Trying an online aptitude test tutorial for Infosys will help you read each topic in detail.
The questions in the previous year’s quiz of Infosys Campus Recruitment are based on various difficulty levels ranging from moderate to easy to difficult.
Infosys Placement Online Test New pattern 2022
- There are total 05 sections for this test
- The duration of the test will be 100 minutes
- It is an adaptive section
- There is no negative marking for this test
Infosys Placement Papers Year 2022: Pattern
| Section Name | Total questions |
|---|---|
| Reasoning Ability | 15 Question |
| Mathematical Ability | 10 Question |
| Verbal Ability | 20 Question |
| Pseudo Code | 05 Question |
| Puzzle Solving | 04 Question |
Infosys Placement Preparation for 2022 Detailed Syllabus (New)
- Mathematical Ability (Quants)
- Reasoning Ability (Logical)
- Cryptarithmetic
- Verbal Ability (English)
- PseudoCode
- Puzzle Solving
Mathematical Ability (Quants) syllabus 2022
- Percentages
- Data Interpretation
- Permutation and Combination
- Probability
- Areas, Shapes, Perimeter
- Speed Time and Distance / Boats and Streams
- Time and Work
- Profit and Loss | Mixtures & Allegation
- Problem on Ages
- Divisibility
- Number Decimal & Fractions
- Series and Progression
- LCM and HCF
Reasoning Ability (Logical) syllabus
- Arrangements
- Puzzles
- Syllogisms
- Coding-Decoding
- Number series
- Cryptarithmetic
- Clocks and Calendar
- Data Sufficiency
- Most logical choice
- Logical deduction
Infosys Verbal English syllabus
- Reading Comprehension
- Sentence Correction
- Sentence selection
- Sentence Completion
- Para Jumbles
- Spotting error
- Analogy
- Fill in the Blanks
- One Word Substitution
- Critical Reasoning
Infosys PseudoCode Syllabus 2022
The Pseudocode round will have cover questions from the following topics:
- Basic of C
- C++
- Data Structures
Cryptarometric Definition
An arithmetic question in which the verbal letters are replaced by numbers and answered by combining all possible digits with letters that form numerically correct solutions or correct answers.
Infosys Placement Paper for Freshers | Infosys Placement Preparation 2022 (New)
| Section | Total questions | Total Time |
|---|---|---|
| Reasoning Ability | 15 Questions | 25 mins |
| Mathematical Ability | 10 Questions | 35 mins |
| Verbal Ability | 20 Questions | 20 mins |
| PseudoCode | 5 Questions | 10 mins |
| Puzzle Solving | 4 Questions | 10 mins |
| Total | 54 Questions | 100 mins |
Infosys Placement Papers with Solutions 2022
| Mathematical Ability (Quants) placement questions 2022 |
Q1: Raj was given a task to arrange the letters of the word ‘SWITZERLAND”. In how many ways can he arrange the letters of the word “SWITZERLAND” so that the positions of the vowels are used by vowels only and the positions of the consonants are used by the consonants only?
Answer: 11!/ 3!
Solutions: In 11 letters we have 3 vowels and 11 consonants.
Q2: If a man is given 5 numerical digits and 4 alphabets, how many alphanumeric words can be formed using exactly 2 digits and 3 alphabets?
Answer: 40
Solutions: 5 C_{ 2}* 4 C^{ 3}= 40
Q3: Find the opposite of Literal
Answer: Dishonest
Solutions: Opposite of Literal is Dishonest
Q4: Ram is a five-year elder to his youngest sibling Shreya. Shreya is two years younger than her brother Ritesh. Ritesh is 13 years old and is Ram’s brother. How old will ram be in two years from now?
Answer: 18
Solutions:
Let shreya’s age be x, then Ram’s age = x+5
Ritesh’s age= x+2
given,
x+2=13
therefore, x=11
hence,
Ram’s age= 16
Ram’s age after 2 yrs=16+2=18 yrs
Q5: What will be the 11th term in the given series: 5, 10, 17, 26, 37, 50, ….. ?
Answer: 145
Solutions:
5-10 = 5
17- 10 = 7
26 – 17 = 9
37 – 26 = 11
We can see that an A.P. is formed of odd numbers .
So the series will be 5, 10, 17, 26, 37, 50, 65, 82, 101, 122, 145…
The 11th term is 145
Q6: One man can do as much work in one day as a woman can do in 2 days. A child does one-third the work in a day as a woman. If an estate owner hires 39 pairs of hands—men, women, and children in the ratio of 6: 5: 2 and pays them in all Rs. 1, 113 at the end of the day’ s work, what must the daily wages of a child be, if the wages are proportional to the amount of work done ?
Answer: Rs.7
Solutions:
Ratio of number of men, women and children = 6 : 5 : 2 and the total number of men, women and children = 39.
Therefore the number of men = 18, women = 15 and children = 6.
Ratio of work done by men:women: children = 6 : 3 : 1
∴ Ratio of work done by 18 men, 15 women and 6 children
= (18 × 6) : (15 × 3) : (6 × 1) = 108 : 45 : 6
Hence Rs.1113 would be divided in this ratio.
That makes Rs756 for men, Rs 315 for women and Rs42 for children. Hence 6 children earn Rs42 in a day. So the daily wage of a child is equal to 42/6 = Rs7
Q7: The number of votes not cast for the PNC Party increased by 25% in the National General Election over those not cast for it in the previous Assembly Polls, and the PNC Party lost by a majority twice as large as that by which it had won the Assembly Polls. If a total 2,60,000 people voted each time, how many voted for the PNC Party in the previous Assembly Polls?
Answer: 140000
Solutions:
Total Votes = 2,60,000
Let x voters voted against the party in the Assembly Poll.
Then votes in favour = 260000 – x
Therefore, majority of votes by which party won in previous poll = 260000– x – x = 260000 – 2x
Next year votes against the PNC party increase by 25%
So, votes against the party in general election = 1.25 x
And votes polled in favour of the party = total votes – votes against = 260000 – 1.25x
Therefore, majority of votes by which party lost in general election
= 1.25x – (260000 – 1.25x) = 2.5x – 260000
It is given that, PNC Party lost by a majority twice as large as that by which it had won the Assembly Polls, Therefore
2.5x – 260000 = 2(260000 – 2 x)
⇒ 2.5x – 260000 = 2 260000 – 4x
⇒ 6.5x = 3260000⇒x == 1,20,000
Therefore, votes polled by the voters for the party in Assembly Polls for previous year
= (2,60,000 – x) = (2,60,000 – 1,20,000) = 1,40,000.
Q7: Find LCM of 12, 15, 20, 27
Answer: 540
Solutions:
Explanation :
12 = 2×2×3 = 2^2 ×3^1
15 = 3× 5
20 = 2×2×5 = 2^2×5
27 = 3×3×3 = 3^3
HCF = 1
LCM = 2^2 × 3^3 × 5 = 540
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Logical Reasoning Infosys Placement Paper |
Solutions:From the above statements, we can make the following diagram 
The position of C and E will remain unchanged. The correct option is (c).
Q2: Who is sitting to the immediate left of E?
Q3: Who is sitting second to the left of A?
Q5: What is the position of F with respect to B?
Answer: None of these
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